SATHEE: Physics And Measurement Question 42

Physics And Measurement Question 42

Question: Whose dimensions is $M L^{2} T^{- 1}$

[CPMT 1989]

Options:

A) Torque

B) Angular momentum

C) Power

D) Work

Show Answer

Answer:

Correct Answer: B

Solution:

Angular momentum = $m v r = M L T^{- 1} \times L = M L^{2} T^{- 1}$

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Physics And Measurement Question 42

Question: Whose dimensions is ML2T−1

Options:

Answer:

Solution:

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Question: Whose dimensions is $M L^{2} T^{- 1}$