Physics And Measurement Question 42

Question: Whose dimensions is $ ML^{2}{{T}^{-1}} $

[CPMT 1989]

Options:

A) Torque

B) Angular momentum

C) Power

D) Work

Show Answer

Answer:

Correct Answer: B

Solution:

Angular momentum = $ mvr=ML{{T}^{-1}}\times L=ML^{2}{{T}^{-1}} $



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