Physics And Measurement Question 42
Question: Whose dimensions is $ ML^{2}{{T}^{-1}} $
[CPMT 1989]
Options:
A) Torque
B) Angular momentum
C) Power
D) Work
Show Answer
Answer:
Correct Answer: B
Solution:
Angular momentum = $ mvr=ML{{T}^{-1}}\times L=ML^{2}{{T}^{-1}} $