[AFMC 1991]
A) $ g(cm/{{\sec }^{2}}) $
B) $ g{{(cm/\sec )}^{2}} $
C) $ g(cm^{2}/\sec ) $
D) $ g(cm/\sec ) $
Correct Answer: B
Potential energy $ =mgh=g( \frac{cm}{{{\sec }^{2}}} )cm=g{{( \frac{cm}{\sec } )}^{2}} $
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