Physics And Measurement Question 333

Question: The unit of potential energy is

[AFMC 1991]

Options:

A) $ g(cm/{{\sec }^{2}}) $

B) $ g{{(cm/\sec )}^{2}} $

C) $ g(cm^{2}/\sec ) $

D) $ g(cm/\sec ) $

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Answer:

Correct Answer: B

Solution:

Potential energy $ =mgh=g( \frac{cm}{{{\sec }^{2}}} )cm=g{{( \frac{cm}{\sec } )}^{2}} $



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