Physics And Measurement Question 313
Question: A suitable unit for gravitational constant is
[MNR 1988]
Options:
A) $ kg\text{-}m{{\sec }^{-1}} $
B) $ N\ {{m}^{-1}}\sec $
C) $ Nm^{2}k{{g}^{-2}} $
D) $ kgm{{\sec }^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ F=\frac{Gm _{1}m _{2}}{d^{2}}; $
$ \therefore $ $ G=\frac{Fd^{2}}{m _{1}m _{2}}=Nm^{2}/kg^{2} $
