Physics And Measurement Question 313

Question: A suitable unit for gravitational constant is

[MNR 1988]

Options:

A) $ kg\text{-}m{{\sec }^{-1}} $

B) $ N\ {{m}^{-1}}\sec $

C) $ Nm^{2}k{{g}^{-2}} $

D) $ kgm{{\sec }^{-1}} $

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Answer:

Correct Answer: C

Solution:

$ F=\frac{Gm _{1}m _{2}}{d^{2}}; $
$ \therefore $ $ G=\frac{Fd^{2}}{m _{1}m _{2}}=Nm^{2}/kg^{2} $



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