Physics And Measurement Question 286
Question: The heat generated in a circuit is given by $ Q=I^{2}Rt $ , where I is current, R is resistance and t is time. If the percentage errors in measuring I, R and t are 2%, 1% and 1% respectively, then the maximum error in measuring heat will be
Options:
A) 2%
B) 3%
C) 4%
D) 6%
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ \frac{\Delta Q}{Q}\times 100=\frac{2\Delta I}{I}\times 100+\frac{\Delta R}{R}\times 100+\frac{\Delta t}{t}\times 100 $
$ =2\times 2%+1%+1%=6% $
