Physics And Measurement Question 286

Question: The heat generated in a circuit is given by $ Q=I^{2}Rt $ , where I is current, R is resistance and t is time. If the percentage errors in measuring I, R and t are 2%, 1% and 1% respectively, then the maximum error in measuring heat will be

Options:

A) 2%

B) 3%

C) 4%

D) 6%

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $ \frac{\Delta Q}{Q}\times 100=\frac{2\Delta I}{I}\times 100+\frac{\Delta R}{R}\times 100+\frac{\Delta t}{t}\times 100 $

$ =2\times 2%+1%+1%=6% $



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