Physics And Measurement Question 276

Question: In the eqn. $ ( P+\frac{a}{V^{2}} )(v-b)=constant $ , the Unit of a is

Options:

A) $ dyne\times cm^{5} $

B) $ dyne\times cm^{4} $

C) $ dyne/cm^{3} $

D) $ dyne\times cm^{2} $

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Answer:

Correct Answer: B

Solution:

[b] As $ \frac{A}{V^{2}}=P $
$ \therefore a=PV^{2}=\frac{dyne}{cm^{2}}{{(cm^{3})}^{2}}=dyne\times cm^{4} $



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