Physics And Measurement Question 276
Question: In the eqn. $ ( P+\frac{a}{V^{2}} )(v-b)=constant $ , the Unit of a is
Options:
A) $ dyne\times cm^{5} $
B) $ dyne\times cm^{4} $
C) $ dyne/cm^{3} $
D) $ dyne\times cm^{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] As $ \frac{A}{V^{2}}=P $
$ \therefore a=PV^{2}=\frac{dyne}{cm^{2}}{{(cm^{3})}^{2}}=dyne\times cm^{4} $
