Physics And Measurement Question 248
Question: If the dimensions of a physical quantity are given by $ M^{a}L^{b}T^{c} $ , then the physical quantity will be
Options:
A) Velocity if $ a=1,b=0,c=-1 $
B) Acceleration if $ a=1,b=1,c=-2 $
C) Force if $ a=0,b=-1,c=-2 $
D) Pressure if $ a=1,b=-1,c=-2 $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Pressure $ =\frac{ML{{T}^{-2}}}{L^{2}}=[M{{L}^{-1}}{{T}^{-2}}] $
$ \Rightarrow a=1,b=-1,c=-2 $
