Physics And Measurement Question 248

Question: If the dimensions of a physical quantity are given by $ M^{a}L^{b}T^{c} $ , then the physical quantity will be

Options:

A) Velocity if $ a=1,b=0,c=-1 $

B) Acceleration if $ a=1,b=1,c=-2 $

C) Force if $ a=0,b=-1,c=-2 $

D) Pressure if $ a=1,b=-1,c=-2 $

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Pressure $ =\frac{ML{{T}^{-2}}}{L^{2}}=[M{{L}^{-1}}{{T}^{-2}}] $
$ \Rightarrow a=1,b=-1,c=-2 $



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