Physics And Measurement Question 209
Question: The momentum of an electron in an orbit is $ h/\lambda $ where A is a constant and $ \lambda $ f is wavelength associated with it. The nuclear magneton of electron of charge e and mass $ m _{e} $ is given as $ {\mu _{n}} $
$ =\frac{eh}{3672\pi m _{e}} $ .The dimensions of $ {\mu _{n}} $ are $ (A\to current) $
Options:
A) $ [ML^{2}A] $
B) $ [ML^{3}A] $
C) $ [L^{2}A] $
D) $ [ML^{2}] $
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Answer:
Correct Answer: C
Solution:
[c] $ {\mu _{n}}=\frac{ATML^{2}{{T}^{-1}}}{M}=L^{2}A $
