Physics And Measurement Question 209

Question: The momentum of an electron in an orbit is $ h/\lambda $ where A is a constant and $ \lambda $ f is wavelength associated with it. The nuclear magneton of electron of charge e and mass $ m _{e} $ is given as $ {\mu _{n}} $

$ =\frac{eh}{3672\pi m _{e}} $ .The dimensions of $ {\mu _{n}} $ are $ (A\to current) $

Options:

A) $ [ML^{2}A] $

B) $ [ML^{3}A] $

C) $ [L^{2}A] $

D) $ [ML^{2}] $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ {\mu _{n}}=\frac{ATML^{2}{{T}^{-1}}}{M}=L^{2}A $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक