Physics And Measurement Question 172
Question: The radius of a sphere is (5.3 ± 0.1) cm. The percentage error in its volume is
Options:
A) $ \frac{0.1}{5.3}\times 100 $
B) $ 3\times \frac{0.1}{5.3}\times 100 $
C) $ \frac{0.1\times 100}{3.53} $
D) $ 3+\frac{0.1}{5.3}\times 100 $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \because V=\frac{4}{3}\pi r^{3} $
% error in volume $ =3\times % $ error in radius. $ =\frac{3\times 0.1}{5.3}\times 100 $
