Physics And Measurement Question 172

Question: The radius of a sphere is (5.3 ± 0.1) cm. The percentage error in its volume is

Options:

A) $ \frac{0.1}{5.3}\times 100 $

B) $ 3\times \frac{0.1}{5.3}\times 100 $

C) $ \frac{0.1\times 100}{3.53} $

D) $ 3+\frac{0.1}{5.3}\times 100 $

Show Answer

Answer:

Correct Answer: B

Solution:

$ \because V=\frac{4}{3}\pi r^{3} $

% error in volume $ =3\times % $ error in radius. $ =\frac{3\times 0.1}{5.3}\times 100 $



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