SATHEE: Physics And Measurement Question 144

Physics And Measurement Question 144

Question: The dimensions of emf in MKS is?

[CPMT 2002]

Options:

A) $M L^{- 1} T^{- 2} Q^{- 2}$

B) $M L^{2} T^{- 2} Q^{- 2}$

C) $M L T^{- 2} Q^{- 1}$

D) $M L^{2} T^{- 2} Q^{- 1}$

Show Answer

Answer:

Correct Answer: D

Solution:

$e = L \frac{d i}{d t} \Rightarrow [e] = [M L^{2} T^{- 2} A^{- 2}] [\frac{A}{T}]$

$[e] = [\frac{M L^{2} T^{- 2}}{A T}] = [M L^{2} T^{- 2} Q^{- 1}]$

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