Physics And Measurement Question 144
Question: The dimensions of emf in MKS is?
[CPMT 2002]
Options:
A) $ M{{L}^{-1}}{{T}^{-2}}{{Q}^{-2}} $
B) $ ML^{2}{{T}^{-2}}{{Q}^{-2}} $
C) $ ML{{T}^{-2}}{{Q}^{-1}} $
D) $ ML^{2}{{T}^{-2}}{{Q}^{-1}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ e=L\frac{di}{dt}\Rightarrow [e]=[ML^{2}{{T}^{-2}}{{A}^{-2}}][ \frac{A}{T} ] $
$ [e]=[ \frac{ML^{2}{{T}^{-2}}}{AT} ]=[ML^{2}{{T}^{-2}}{{Q}^{-1}}] $
