Physics And Measurement Question 144

Question: The dimensions of emf in MKS is?

[CPMT 2002]

Options:

A) $ M{{L}^{-1}}{{T}^{-2}}{{Q}^{-2}} $

B) $ ML^{2}{{T}^{-2}}{{Q}^{-2}} $

C) $ ML{{T}^{-2}}{{Q}^{-1}} $

D) $ ML^{2}{{T}^{-2}}{{Q}^{-1}} $

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Answer:

Correct Answer: D

Solution:

$ e=L\frac{di}{dt}\Rightarrow [e]=[ML^{2}{{T}^{-2}}{{A}^{-2}}][ \frac{A}{T} ] $

$ [e]=[ \frac{ML^{2}{{T}^{-2}}}{AT} ]=[ML^{2}{{T}^{-2}}{{Q}^{-1}}] $



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