SATHEE: Optics Question 987

Optics Question 987

Question: If light travels a distance x in $t_{1}$ sec in air and 10 x distance in $t_{2}$ sec in a medium, the critical angle of the medium will be

[MH CET 2003]

Options:

A) $\tan^{- 1} (\frac{t_{1}}{t_{2}})$

B) $\sin^{- 1} (\frac{t_{1}}{t_{2}})$

C) $\sin^{- 1} (\frac{10 t_{1}}{t_{2}})$

D) $\tan^{- 1} (\frac{10 t_{1}}{t_{2}})$

Show Answer

Answer:

Correct Answer: C

Solution:

From the formula $\sin C = \frac{1}{_{1} μ_{2}}$

$\Rightarrow \sin C =_{2} μ_{1}$

$= \frac{u_{1}}{u_{2}} = \frac{v_{2}}{v_{1}}$

$\Rightarrow \sin C = \frac{10 x / t_{2}}{x / t_{1}}$

$\Rightarrow \sin C = \frac{10 t_{1}}{t_{2}}$

$\Rightarrow C = \sin^{- 1} (\frac{10 t_{1}}{t_{2}})$

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Optics Question 987

Question: If light travels a distance x in t1 sec in air and 10 x distance in t2 sec in a medium, the critical angle of the medium will be

Options:

Answer:

Solution:

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Question: If light travels a distance x in $t_{1}$ sec in air and 10 x distance in $t_{2}$ sec in a medium, the critical angle of the medium will be