Optics Question 987

Question: If light travels a distance x in $ t _{1} $ sec in air and 10 x distance in $ t _{2} $ sec in a medium, the critical angle of the medium will be

[MH CET 2003]

Options:

A) $ {{\tan }^{-1}}( \frac{t _{1}}{t _{2}} ) $

B) $ {{\sin }^{-1}}( \frac{t _{1}}{t _{2}} ) $

C) $ {{\sin }^{-1}}( \frac{10t _{1}}{t _{2}} ) $

D) $ {{\tan }^{-1}}( \frac{10t _{1}}{t _{2}} ) $

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Answer:

Correct Answer: C

Solution:

From the formula $ \sin C=\frac{1}{ _{1}{\mu _{2}}} $

$ \Rightarrow \sin C{= _{2}}{\mu _{1}} $

$ =\frac{u _{1}}{u _{2}}=\frac{v _{2}}{v _{1}} $

$ \Rightarrow \sin C=\frac{10x/t _{2}}{x/t _{1}} $

$ \Rightarrow \sin C=\frac{10t _{1}}{t _{2}} $

$ \Rightarrow C={{\sin }^{-1}}( \frac{10t _{1}}{t _{2}} ) $



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