Optics Question 983

Question: The critical angle for a medium is $ 60^{o} $ . The refractive index of the medium is

[MP PMT 2004]

Options:

A) $ \frac{2}{\sqrt{3}} $

B) $ \frac{\sqrt{2}}{3} $

C) $ \sqrt{3} $

D) $ \frac{\sqrt{3}}{2} $

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Answer:

Correct Answer: A

Solution:

$ \mu =\frac{1}{\sin C}=\frac{1}{\sin 60^{o}} $

$ =\frac{2}{\sqrt{3}} $



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