Optics Question 983
Question: The critical angle for a medium is $ 60^{o} $ . The refractive index of the medium is
[MP PMT 2004]
Options:
A) $ \frac{2}{\sqrt{3}} $
B) $ \frac{\sqrt{2}}{3} $
C) $ \sqrt{3} $
D) $ \frac{\sqrt{3}}{2} $
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Answer:
Correct Answer: A
Solution:
$ \mu =\frac{1}{\sin C}=\frac{1}{\sin 60^{o}} $
$ =\frac{2}{\sqrt{3}} $