Optics Question 889

Question: A polaroid is placed at $ 45{}^\circ $ to an incoming light of intensity I. Now the intensity of light after polarisation would be

Options:

A) I

B) $ I/2 $

C) $ I/\sqrt{2} $

D) zero

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $ I’=I{{\cos }^{2}}\theta =I{{\cos }^{2}}(45^{o})=I{{( \frac{I}{\sqrt{2}} )}^{2}}=\frac{I}{2} $



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