Optics Question 889
Question: A polaroid is placed at $ 45{}^\circ $ to an incoming light of intensity I. Now the intensity of light after polarisation would be
Options:
A) I
B) $ I/2 $
C) $ I/\sqrt{2} $
D) zero
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ I’=I{{\cos }^{2}}\theta =I{{\cos }^{2}}(45^{o})=I{{( \frac{I}{\sqrt{2}} )}^{2}}=\frac{I}{2} $
