Optics Question 886

Question: The first diffraction minimum due to the single slit diffraction is seen at 9=30 for a light of wavelength 5000 A falling perpendicularly on the slit. The width of the slit is

Options:

A) 2.5×105cm

B) 1.25×105cm

C) 10×105cm

D) 5×105cm

Show Answer

Answer:

Correct Answer: C

Solution:

[c] For first minimum, dsinθ=λ

d=λsinθ=5000×108cmsin30o

=5000×108cm1/2=10×105cm



NCERT Chapter Video Solution

Dual Pane