Optics Question 739

Question: The distance travelled by light in glass (refractive index =1.5) in a nanosecond will be

[MP PET 1999]

Options:

A) 45 cm

B) 40 cm

C) 30 cm

D) 20 cm

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Answer:

Correct Answer: D

Solution:

Distance = $ v\times t=\frac{c}{\mu }\times t=\frac{3\times 10^{8}}{1.5}\times {{10}^{-9}} $ = 0.2 m = 20 cm.



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