Optics Question 739
Question: The distance travelled by light in glass (refractive index =1.5) in a nanosecond will be
[MP PET 1999]
Options:
A) 45 cm
B) 40 cm
C) 30 cm
D) 20 cm
Show Answer
Answer:
Correct Answer: D
Solution:
Distance = $ v\times t=\frac{c}{\mu }\times t=\frac{3\times 10^{8}}{1.5}\times {{10}^{-9}} $ = 0.2 m = 20 cm.
