Optics Question 497

Question: The intensity of direct sunlight on a surface normal to the rays is $ I _{0} $ . What is the intensity of direct sunlight on a surface, whose normal makes an angle of 60o with the rays of the sun

[CPMT 1981]

Options:

A) $ I _{0} $

B) $ I _{0}( \frac{\sqrt{3}}{2} ) $

C) $ \frac{I _{0}}{2} $

D) $ 2I _{0} $

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Answer:

Correct Answer: C

Solution:

$ {I _{\theta }}=I _{o}\cos \theta $

$ =I _{o}\cos 60^{o} $

$ =\frac{I _{o}}{2} $



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