SATHEE: Optics Question 497

Optics Question 497

Question: The intensity of direct sunlight on a surface normal to the rays is $I_{0}$ . What is the intensity of direct sunlight on a surface, whose normal makes an angle of 60o with the rays of the sun

[CPMT 1981]

Options:

A) $I_{0}$

B) $I_{0} (\frac{\sqrt{3}}{2})$

C) $\frac{I_{0}}{2}$

D) $2 I_{0}$

Show Answer

Answer:

Correct Answer: C

Solution:

$I_{θ} = I_{o} \cos θ$

$= I_{o} \cos 60^{o}$

$= \frac{I_{o}}{2}$

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Optics Question 497

Question: The intensity of direct sunlight on a surface normal to the rays is I0 . What is the intensity of direct sunlight on a surface, whose normal makes an angle of 60o with the rays of the sun

Options:

Answer:

Solution:

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Question: The intensity of direct sunlight on a surface normal to the rays is $I_{0}$ . What is the intensity of direct sunlight on a surface, whose normal makes an angle of 60o with the rays of the sun