Optics Question 297

Question: In an apparatus, the electric field was found to oscillate with an amplitude of 18 V/m. The magnitude of the oscillating magnetic field will be

[Pb. PMT 1999]

Options:

A) $ 4\times {{10}^{-6}} $ T

B) $ 6\times {{10}^{-8}} $ T

C) $ 9\times {{10}^{-9}} $ T

D) $ 11\times {{10}^{-11}} $ T

Show Answer

Answer:

Correct Answer: B

Solution:

$ c=\frac{E}{B}\Rightarrow B=\frac{E}{c}=\frac{18}{3\times 10^{8}}=6\times {{10}^{-8}}T $ .



NCERT Chapter Video Solution

Dual Pane