Optics Question 297
Question: In an apparatus, the electric field was found to oscillate with an amplitude of 18 V/m. The magnitude of the oscillating magnetic field will be
[Pb. PMT 1999]
Options:
A) $ 4\times {{10}^{-6}} $ T
B) $ 6\times {{10}^{-8}} $ T
C) $ 9\times {{10}^{-9}} $ T
D) $ 11\times {{10}^{-11}} $ T
Show Answer
Answer:
Correct Answer: B
Solution:
$ c=\frac{E}{B}\Rightarrow B=\frac{E}{c}=\frac{18}{3\times 10^{8}}=6\times {{10}^{-8}}T $ .
