SATHEE: Optics Question 233

Optics Question 233

Question: The width of the nth HPZ will be

Options:

A) $\sqrt{n b λ}$

B) $\sqrt{b λ} [\sqrt{n} - \sqrt{n - 1}]$

C) $(\sqrt{n} - \sqrt{n - 1})$

D) $\frac{\sqrt{b λ}}{[\sqrt{n} - \sqrt{n - 1}]}$

Show Answer

Answer:

Correct Answer: B

Solution:

Width of nth HPZ $B_{n} = r_{n} - r_{n - 1}$

$r_{n} = \sqrt{n b λ}$ , $r_{n - 1} = \sqrt{(n - 1) b λ}$

$B_{n} = \sqrt{n b λ} - \sqrt{(n - 1) b λ} = \sqrt{b λ} [\sqrt{n} - \sqrt{(n - 1)}]$

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Optics Question 233

Question: The width of the nth HPZ will be

Options:

Answer:

Solution:

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