Optics Question 173

Question: Among the two interfering monochromatic sources A and B; A is ahead of B in phase by 66°. If the observation be taken from point P, such that PB ? PA = l/4. Then the phase difference between the waves from A and B reaching P is

Options:

A) 156°

B) 140°

C) 136°

D) 126°

Show Answer

Answer:

Correct Answer: A

Solution:

Total phase difference = Initial phase difference + Phase difference due to path $ =66{}^\circ +\frac{360{}^\circ }{\lambda }\times \Delta x $

$ =66{}^\circ +\frac{360{}^\circ }{\lambda }\times \frac{\lambda }{4} $

$ =66{}^\circ +90=156{}^\circ $



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