Optics Question 173
Question: Among the two interfering monochromatic sources A and B; A is ahead of B in phase by 66°. If the observation be taken from point P, such that PB ? PA = l/4. Then the phase difference between the waves from A and B reaching P is
Options:
A) 156°
B) 140°
C) 136°
D) 126°
Show Answer
Answer:
Correct Answer: A
Solution:
Total phase difference = Initial phase difference + Phase difference due to path $ =66{}^\circ +\frac{360{}^\circ }{\lambda }\times \Delta x $
$ =66{}^\circ +\frac{360{}^\circ }{\lambda }\times \frac{\lambda }{4} $
$ =66{}^\circ +90=156{}^\circ $
