Optics Question 1144

Question: In Young’s double slit experiment the amplitudes of two sources are 3a and a respectively. The ratio of intensities of bright and dark fringes will be

[J & K CET 2004]

Options:

A) 3 : 1

B) 4 : 1

C) 2 : 1

D) 9 : 1

Show Answer

Answer:

Correct Answer: B

Solution:

$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{a _{1}+a _{2}}{a _{1}-a _{2}} )}^{2}}={{( \frac{3a+a}{3a-a} )}^{2}}=\frac{4}{1} $



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