Optics Question 1144
Question: In Young’s double slit experiment the amplitudes of two sources are 3a and a respectively. The ratio of intensities of bright and dark fringes will be
[J & K CET 2004]
Options:
A) 3 : 1
B) 4 : 1
C) 2 : 1
D) 9 : 1
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{a _{1}+a _{2}}{a _{1}-a _{2}} )}^{2}}={{( \frac{3a+a}{3a-a} )}^{2}}=\frac{4}{1} $
