Optics Question 1141

Question: The two slits at a distance of 1 mm are illuminated by the light of wavelength 6.5×107m . The interference fringes are observed on a screen placed at a distance of 1m. The distance between third dark fringe and fifth bright fringe will be

[NCERT 1982; MP PET 1995; BVP 2003]

Options:

A) 0.65 mm

B) 1.63 mm

C) 3.25 mm

D) 4.88 mm

Show Answer

Answer:

Correct Answer: B

Solution:

Distance between nth Bright fringe and mth dark fringe (n>m)

Δx=(nm+12)β=(53+12)×6.5×107×11×103 = 1.63mm



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