Optics Question 1141

Question: The two slits at a distance of 1 mm are illuminated by the light of wavelength $ 6.5\times {{10}^{-7}}m $ . The interference fringes are observed on a screen placed at a distance of 1m. The distance between third dark fringe and fifth bright fringe will be

[NCERT 1982; MP PET 1995; BVP 2003]

Options:

A) 0.65 mm

B) 1.63 mm

C) 3.25 mm

D) 4.88 mm

Show Answer

Answer:

Correct Answer: B

Solution:

Distance between $ n^{th} $ Bright fringe and $ m^{th} $ dark fringe $ (n>m) $

$ \Delta x=( n-m+\frac{1}{2} )\beta =( 5-3+\frac{1}{2} )\times \frac{6.5\times {{10}^{-7}}\times 1}{1\times {{10}^{-3}}} $ = $ 1.63mm $



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