SATHEE: Optics Question 1122

Optics Question 1122

Question: In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1. The amplitudes of the coherent sources are in the ratio

[RPMT 1996; MP PET 2000; RPET 2001; MP PMT 2001]

Options:

A) 4 : 1

B) 3 : 1

C) 2 : 1

D) 1 : 1

Show Answer

Answer:

Correct Answer: B

Solution:

$\frac{I_{max}}{I_{min}} = \frac{{(\frac{a_{1}}{a_{2}} + 1)}^{2}}{{(\frac{a_{1}}{a_{2}} - 1)}^{2}} = \frac{4}{1} \Rightarrow \frac{a_{1}}{a_{2}} = \frac{3}{1}$

Optics Question 1122

Question: In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1. The amplitudes of the coherent sources are in the ratio

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Optics Question 1122

Question: In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1. The amplitudes of the coherent sources are in the ratio

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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