Optics Question 1122
Question: In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1. The amplitudes of the coherent sources are in the ratio
[RPMT 1996; MP PET 2000; RPET 2001; MP PMT 2001]
Options:
A) 4 : 1
B) 3 : 1
C) 2 : 1
D) 1 : 1
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{{I _{\max }}}{{I _{\min }}}=\frac{{{( \frac{a _{1}}{a _{2}}+1 )}^{2}}}{{{( \frac{a _{1}}{a _{2}}-1 )}^{2}}}=\frac{4}{1}\Rightarrow \frac{a _{1}}{a _{2}}=\frac{3}{1} $
