Optics Question 1122

Question: In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1. The amplitudes of the coherent sources are in the ratio

[RPMT 1996; MP PET 2000; RPET 2001; MP PMT 2001]

Options:

A) 4 : 1

B) 3 : 1

C) 2 : 1

D) 1 : 1

Show Answer

Answer:

Correct Answer: B

Solution:

$ \frac{{I _{\max }}}{{I _{\min }}}=\frac{{{( \frac{a _{1}}{a _{2}}+1 )}^{2}}}{{{( \frac{a _{1}}{a _{2}}-1 )}^{2}}}=\frac{4}{1}\Rightarrow \frac{a _{1}}{a _{2}}=\frac{3}{1} $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक