Optics Question 1105

Question: In Young’s double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is 4×107m . If the width of the fringe on the screen is 4 mm, the distance between screen and slit is

[Bihar CMEET 1995]

Options:

A) 0.1 mm

B) 1 cm

C) 0.1 cm

D) 1 m

Show Answer

Answer:

Correct Answer: D

Solution:

β=λDd(4×103)=4×107×D0.1×103D=1m



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