Optics Question 1105

Question: In Young’s double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is $ 4\times {{10}^{-7}}m $ . If the width of the fringe on the screen is 4 mm, the distance between screen and slit is

[Bihar CMEET 1995]

Options:

A) 0.1 mm

B) 1 cm

C) 0.1 cm

D) 1 m

Show Answer

Answer:

Correct Answer: D

Solution:

$ \beta =\frac{\lambda D}{d}\Rightarrow (4\times {{10}^{-3}})=\frac{4\times {{10}^{-7}}\times D}{0.1\times {{10}^{-3}}}\Rightarrow D=1m $



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