Optics Question 1095

Question: In a biprism experiment, by using light of wavelength 5000 Å, 5 mm wide fringes are obtained on a screen 1.0 m away from the coherent sources. The separation between the two coherent sources is

[MP PMT/PET 1998]

Options:

A) 1.0 mm

B) 0.1 mm

C) 0.05 mm

D) 0.01 mm

Show Answer

Answer:

Correct Answer: B

Solution:

$ d=\frac{D\lambda }{\beta }=\frac{1\times 5\times {{10}^{-7}}}{5\times {{10}^{-3}}}={{10}^{-4}}m=0.1\ mm $ .



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