Optics Question 1095
Question: In a biprism experiment, by using light of wavelength 5000 Å, 5 mm wide fringes are obtained on a screen 1.0 m away from the coherent sources. The separation between the two coherent sources is
[MP PMT/PET 1998]
Options:
A) 1.0 mm
B) 0.1 mm
C) 0.05 mm
D) 0.01 mm
Show Answer
Answer:
Correct Answer: B
Solution:
$ d=\frac{D\lambda }{\beta }=\frac{1\times 5\times {{10}^{-7}}}{5\times {{10}^{-3}}}={{10}^{-4}}m=0.1\ mm $ .
