Optics Question 1051
Question: Intensities of the two waves of light are I and 4I. The maximum intensity of the resultant wave after superposition is
[MP PET 2002]
Options:
A) 5 I
B) 9 I
C) 16 I
D) 25 I
Show Answer
Answer:
Correct Answer: B
Solution:
$ {I _{\max }}=I _{1}+I _{2}+2\sqrt{I _{1}I _{2}} $ .
So, $ {I _{\max }}=I+4I+2\sqrt{I.4I}=9I $
