Optics Question 1051

Question: Intensities of the two waves of light are I and 4I. The maximum intensity of the resultant wave after superposition is

[MP PET 2002]

Options:

A) 5 I

B) 9 I

C) 16 I

D) 25 I

Show Answer

Answer:

Correct Answer: B

Solution:

$ {I _{\max }}=I _{1}+I _{2}+2\sqrt{I _{1}I _{2}} $ .

So, $ {I _{\max }}=I+4I+2\sqrt{I.4I}=9I $



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