Optics Question 1050

Question: If an interference pattern have maximum and minimum intensities in 36 : 1 ratio then what will be the ratio of amplitudes

[AFMC 2002]

Options:

A) 5 : 7

B) 7 : 4

C) 4 : 7

D) 7 : 5

Show Answer

Answer:

Correct Answer: D

Solution:

$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\frac{a _{1}}{a _{2}}+1}{\frac{a _{1}}{a _{2}}-1} )}^{2}}\Rightarrow \frac{a _{1}+a _{2}}{a _{1}-a _{2}}=6 $

$ \frac{a _{2}}{a _{1}}=7:5 $



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