Optics Question 1050
Question: If an interference pattern have maximum and minimum intensities in 36 : 1 ratio then what will be the ratio of amplitudes
[AFMC 2002]
Options:
A) 5 : 7
B) 7 : 4
C) 4 : 7
D) 7 : 5
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\frac{a _{1}}{a _{2}}+1}{\frac{a _{1}}{a _{2}}-1} )}^{2}}\Rightarrow \frac{a _{1}+a _{2}}{a _{1}-a _{2}}=6 $
$ \frac{a _{2}}{a _{1}}=7:5 $
