SATHEE: Optics Question 1032

Optics Question 1032

Question: Two coherent sources have intensity in the ratio of $\frac{100}{1}$ . Ratio of (intensity) max/(intensity) min is

[RPET 2000]

Options:

A) $\frac{1}{100}$

B) $\frac{1}{10}$

C) $\frac{10}{1}$

D) $\frac{3}{2}$

Show Answer

Answer:

Correct Answer: D

Solution:

$\frac{I_{1}}{I_{2}} = \frac{100}{1}$ Now $\frac{I_{max}}{I_{min}} = {(\frac{\sqrt{\frac{I_{1}}{I_{2}}} + 1}{\sqrt{\frac{I_{1}}{I_{2}}} - 1})}^{2} = {(\frac{\sqrt{100} + 1}{\sqrt{100} - 1})}^{2} = \frac{121}{81} \approx \frac{3}{2}$

Optics Question 1032

Question: Two coherent sources have intensity in the ratio of $\frac{100}{1}$ . Ratio of (intensity) max/(intensity) min is

Options:

Answer:

Solution:

Engineering Preparation

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Optics Question 1032

Question: Two coherent sources have intensity in the ratio of 1001 . Ratio of (intensity) max/(intensity) min is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Two coherent sources have intensity in the ratio of $\frac{100}{1}$ . Ratio of (intensity) max/(intensity) min is