Optics Question 1032
Question: Two coherent sources have intensity in the ratio of $ \frac{100}{1} $ . Ratio of (intensity) max/(intensity) min is
[RPET 2000]
Options:
A) $ \frac{1}{100} $
B) $ \frac{1}{10} $
C) $ \frac{10}{1} $
D) $ \frac{3}{2} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{I _{1}}{I _{2}}=\frac{100}{1} $ Now $ \frac{{I _{\max }}}{{I _{\min }}}={{( \frac{\sqrt{\frac{I _{1}}{I _{2}}}+1}{\sqrt{\frac{I _{1}}{I _{2}}}-1} )}^{2}}={{( \frac{\sqrt{100}+1}{\sqrt{100}-1} )}^{2}}=\frac{121}{81}\approx \frac{3}{2} $
